Course of Raku / Addendum 🆕 / Types and text machines / Objects and classes / Exercises / Which quadrant

Solution: Which quadrant

Here is a possible solution to the task.

Code

class Point {
    has $.x;
    has $.y;

    method quadrant {
        return 'origin'     if $.x == 0 && $.y == 0;
        return 'on an axis' if $.x == 0 || $.y == 0;
        return $.x > 0 ?? ($.y > 0 ?? 'first'  !! 'fourth')
                       !! ($.y > 0 ?? 'second' !! 'third');
    }
}

for Point.new(x => 3, y => 4),  Point.new(x => -2, y => 5),
    Point.new(x => -1, y => -6), Point.new(x => 0, y => 3) -> $point {
    say "({$point.x}, {$point.y}): {$point.quadrant}";
}

🦋 You can find the source code in the file point-quadrant.raku.

Output

(3, 4): first
(-2, 5): second
(-1, -6): third
(0, 3): on an axis

Comments

1. The two early returns handle the special cases first — the origin and points lying on an axis — so the rest of the method can assume both coordinates are non-zero.

2. The nested ternary then reads off the quadrant from the signs of x and y: a positive x means the first or fourth quadrant, a negative x the second or third.

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